Homework SourseWhats wrong with this Hardy Weinberg question I thought it w
What\'s wrong with this Hardy Weinberg question?? I thought it was answered correctly.
Within a population of butterflies, the allele for the color black (B) is incompletely dominant over the allele for the color white (b). A survey of the population finds 42 black butterflies, 47 white butterflies, and 11 gray butterflies.
Is this population in HW equilibrium? Show your work
o 42+47+11= 100
o Since black color is incompletely dominant over white then since white is recessive, q2 = 47/100= .47
o p2 =42/100= .42
o Also according to HWE p+q=1
o This population is not in hardyweinberg equation according to above formula
Describe what might explain the phenotype and genotype proportions we see in this population.
Mendel’s results were groundbreaking partly because they contradicted the (then-popular) idea that parents\' traits were permanently blended in their offspring. In some cases, however, the phenotype of a heterozygous organism can actually be a blend between the phenotypes of its homozygous parents. The type of relationship between alleles with a heterozygote phenotype intermediate between the two homozygote phenotypes is called incomplete dominance.
Solution
No this is not in equilibirium as p+q isnot equal to 1.
it is 0.47+042=0.89
The phenotyype propotion is 0.47/0.42=>0.89
as it shows it is shor t by 0.11 .the equation is not satisfied .
