calculate the mass defect of a deuterium nucleus Mdeuterium

calculate the mass defect of a deuterium nucleus. ( Mdeuterium= 2.014102 amu , Mneutrons = 1.008665 , Mprotons = 1.007276 )

B. calculate the binding energy (1 amu = 931meV)

Solution

We know that deuterium nucleus has 1 neutron and 1 proton

mass of 1 proton =    1.007276 amu

mass of 1 neutron =   1.008665 amu

Total                     =    2.015941 amu

given that mass of deuterium = 2.014102 amu

hence defect of mass = 2.015941 - 2.014102 = 0.001839 amu.............Ans.

B. Binding Energy = 0.001839 * 931 = 1.712109 MeV...........Ans.