Z is a standard normal random variable The P120 Z 150 equals
     Z is a standard normal random variable. The P(-1.20  Z  1.50) equals 
  
  Solution
Mean ( u ) =0
 Standard Deviation ( sd )=1
 Normal Distribution = Z= X- u / sd ~ N(0,1)                  
 To find P(a < = Z < = b) = F(b) - F(a)
 P(X < -1.2) = (-1.2-0)/1
 = -1.2/1 = -1.2
 = P ( Z <-1.2) From Standard Normal Table
 = 0.11507
 P(X < 1.5) = (1.5-0)/1
 = 1.5/1 = 1.5
 = P ( Z <1.5) From Standard Normal Table
 = 0.93319
 P(-1.2 < X < 1.5) = 0.93319-0.11507 = 0.8181

