Inductors in series Two inductors L1 1 30 H and L2 2 16 H a

Inductors in series. Two inductors L_1= 1. 30 H and L_2 - 2. 16 H are connected in series and are separated by a large distance so that the magnetic field of one cannot affect the other, (a) Calculate the equivalent inductance.

Solution

Inductor in Seried

L eqv = L1+L2 = 1.30 +2.16 = 3.46 H

It is similar to resistors in series

b) For N similar inductor

Leqv = N * L

= 36 * 3.08 =110.88 H