12 6 points A sample of 12 digital temperature of a certain
Solution
Formulating the null and alternative hypotheses,              
               
 Ho:   u   =   100  
 Ha:    u   =/   100  
               
 As we can see, this is a    two   tailed test.      
               
 Thus, getting the critical t,              
 df = n - 1 =    11          
 tcrit =    +/-   2.20098516      
               
 Getting the test statistic, as              
               
 X = sample mean =    97.075          
 uo = hypothesized mean =    100          
 n = sample size =    12          
 s = standard deviation =    6.109474758          
               
 Thus, t = (X - uo) * sqrt(n) / s =    -1.658489089          
               
 Also, the p value is              
               
 p =    0.125430773          
               
 As |t| < 2.201, or P > 0.05, we   FAIL TO REJECT THE NULL HYPOTHESIS.          
Thus, there is no significant evidence that the thermometer\'s mean reading under these conditions is different from 100 degrees C. [CONCLUSION]
![12. [6 points] A sample of 12 digital temperature of a certain type was selected, and each was tested in an oven where the true temperature was 100 C. The resu  12. [6 points] A sample of 12 digital temperature of a certain type was selected, and each was tested in an oven where the true temperature was 100 C. The resu](/WebImages/30/12-6-points-a-sample-of-12-digital-temperature-of-a-certain-1082740-1761568855-0.webp)
