Given that fx x2 3 and gx 2x 1 1xfg squareroot 3 2gf12 S

Given that f(x) = x^2 3 and g(x) = 2x + 1 1.x(f/g) (- squareroot 3) 2.(g/f)(-1/2)

Solution

f(x) = x^2 -3 ;

g(x) = 2x +1

(f/g) = f(x)/g(x) = (x^2 -3)/(2x+1)

plug x= -sqrt3

(f/g)(-sqrt3) = (3-3)/(2*-sqrt3 +1) =0

(g/f)(x) = g(x)/f(x) = (2x+1)/(x^2 -3)

plug x= -1/2

(g/f)(-1/2) = (2*(-1/2) +1) /( 1/4 -3) = 0