Make an 8x8 matrix of integers then set each value as follow

Make an 8x8 matrix of integers, then set each value as follows.

8 7 6 5 4 3 2 1
16 15 14 13 12 11 10 9
24 23 22 21 20 19 18 17
32 31 30 29 28 27 26 25
40 39 38 37 36 35 34 33
48 47 46 45 44 43 42 41
56 55 54 53 52 51 50 49
64 63 62 61 60 59 58 57

Print the matrix so that the columns line up, using at least 2 places for each value, at least 1 space between each column, and a new-line after each row.

Here is my code:

int main ()

{

int T[10][10],l,c,i;

l=10;

c=10;

for(int j=0;i<l;i++){

printf(\"\ \");

for(int j=0;j<c;j++){

printf(T[i][j]);

}

}

return 0;

}

Solution

#include <stdio.h>
int main()
{
   int i,j;
   for(i=1;i<=8;i++)
   {
       for(j=i*8;j>8*(i-1);j--)
       {
           if(j<i*8)
           {
               printf(\" \");
           }
           if(j<10)
           {
               printf(\" \");
           }
           printf(\"%d\",j);
       }
       printf(\"\ \");
   }

   return 0;
}