In the circuit below if the load resistance RLOAD was 3k3 33

In the circuit below, if the load resistance R_LOAD was 3k3 (3300) ohms, to what voltage could the 9V battery\'s voltage fall, before the regulators output voltage of 5.1V would start to drop. Assume that the Zener diode needs at least 1mA flowing through it to hold the reverse breakover voltage of 5.1V.

Give the answer in volts without including the units (numerical answer only) 1k 9 5V1 R LOAD

Ans) Let us assume that Zener Diode is working with least current of 1mA to calulate how much battery voltage can fall

The output Voltage =Zener Voltage is =Vo=5.1 V

Rload=3.3 K

Output current Io=Vo/Rload=5.1/3.3K=1.545 mA

Zener current Iz=1mA

Using KCL total input current at node=Is=Iz+Io=1+1.545=2.545 mA

Is=2.545 mA

Voltage drop across 1k Resistor Vd=Is*1K=2.545 V

Vd=2.545 V

Now using KVL Vbattery=Vz+Vd=5.1+2.545

(Battery Voltage) Vbattery=7.645 V

So battery voltage can drop to 7.645 V ,if it falls below that this zener current will be less than 1 mA leads to decrease in output Voltage

$In the circuit below, if the load resistance RLOAD was 3k3 (3300) ohms, to what voltage could the 9V battery\'s voltage fall, before the regulators output volta$

In the circuit below if the load resistance RLOAD was 3k3 33

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