Women between the ages of 40 and 44 have only a 37 chance of

Women between the ages of 40 and 44 have only a 37% chance of being able to bear a child. Joan, Janice, and Jennifer are friends, all in the 40 to 44 age grouo, and all are trying to have a child. Assume they are representative of a random of sample of women in this age group.

A. What is the probabaility that Joan will not be able to bear a child?

B. What is the probability that none of the three women will be able to bear a child?

C. What is the probability that at least one of the women will be able to bear a child?

Thanks.

Solution

Probability of a women bearing a child = 37/100

robability of a women will not bear a child = 63/100

Probability of Joan not bearing a child = 3C₁ (63/100)(37/100)² = 0.258(ans)

Probability that none of the 3 will bear a child = 3C₃ (0.63)³= 0.2500 (ans)

Probability that at least one of them will be able to bear a child = 1- P(NOne of them will be able to bear a child)

                                                                                            = 1- 0.2500 =0.7500 (ans)