ChiSquare Test for Independence Using ChiSquare we are looki

Chi-Square Test for Independence Using Chi-Square, we are looking to see if there is a significant difference between what we would expect results to be, and what the actual results were. That is, expected vs. observed. Use alpha = .05 Listed below are data from a survey conducted recently where Males and Females responded to their happiness with their supervisor (this is fictitious data).

Response Male Female Total

Not at all     23      25      48

Somewhat 13        22      35

Very            26       16       42

Total            62       63      125

What is your null hypothesis?

What is your alternative hypothesis?

What is the Chi-Square value?

Is there significance evidence that a difference exists between the actual males and female responses in this sample and the expected male/female responses in the population? YES OR NO

Solution

The null hypothesis will be

H₀: the males and females are happy with their supervisors.

and , The alternative hypotheses will be

H₁: The males and females are not happy wit their supervisor.

H₂: the males and females are somewhat happy with their supervisor.