Three resistors are connected across a battery as shown in t

Three resistors are connected across a battery as shown in the figure. How much power is dissipated across the three resistors? Determine the potential drop across each resistor.

Solution

Req = 192 + 192/2 ( 192 ohm is in series with two parallel resistances )

Req = 288

first let\'s do part b)

=> voltage drop to both 192 ohm in parallel = 192*120)/(2*288) = 40 V

Voltage drop to 192 ohm in series = 192*120)/(288) = 80 V

a) power dissipated = V^2/R

=>   power dissipated in 192 in series = 80^2/(192) = 33.33 Watt

power dissipated in two 192 in paralle = 40^2/(192) = 8.333Watt