Your answer should contain only positive exponents v23 4n2 x
Your answer should contain only positive exponents. (v^-2)^3 (4n)^2 (x^2)^-4 (2x^0)4 2x/8x^2 3a^4/8a 8a^4/4a^2 6x/4x
Solution
Use the exponent propert: a^-n = 1/a^n : (a^m)^n = a^(m*n) ; a^m/a^n = a^(m-n)
1) (v^-2)^3 = v^(-2*3) = v^-6 = 1/v^6
2) (4n)^2 = (4^2)(n^2) = 16n^2
3) (x^2)^-4 = x^(2*-4) = x^-8 = 1/x^8
4) (2x^0)^4 = (2^4)(x^0*4) = 16*1 = 16 ( By Propert : a^0 = 1)
5) 2x/8x^2 = 2x/(2^3)(x^2) = 2^(1-3)*(x^(1-2) = (2^-2)x^-1
= 1/2^2x = 1/4x
8) 6x/4x = (6/4)(x^(1-1)) = (3/2)*1 = 3/2
