A simple random sample of 11 observations is derived from a
| A simple random sample of 11 observations is derived from a normally distributed population with a known standard deviation of 2.2. Use Table 1. | 
Solution
a)
 Yes
 b)
 Margin of Error = Z a/2 * (sd/ Sqrt(n))
 Where,
 x = Mean
 sd = Standard Deviation
 a = 1 - (Confidence Level/100)
 Za/2 = Z-table value
 Mean(x)=8.36
 Standard deviation( sd )=2.2
 Sample Size(n)=11
 Margin of Error = Z a/2 * 2.2/ Sqrt ( 11)
 = 2.17 * (0.663)
 = 1.439
 c)
Margin of Error = Z a/2 * 2.2/ Sqrt ( 11)
 = 2.58 * (0.663)
 = 1.711
 d)
 The margin of error with 99% confidence.

