Find the equation of a line that is perpendicular to the lin

Find the equation of a line that is perpendicular to the line y = 1/9x + 5 and contains the point (-5, 0). y = (Type your answer in slope-intercept from.)

Solution

Line perpendicular to y = x/9 + 5 would have a slope of

m = -9

slope interecept form of equation : y = mx+c

y = -9x +c and a point containing (-5,0)

0 = -9*(-5) +c ---> c = -45

y = -9x -45