Given rt cos t sin t tfind the velocity acceleration and sp
Solution
Velocity is given by r\'
r\'=<-sin(t),cos(t),1>
At t=pi/2 it takes teh value
r\'=<-1,0,1>
Acceleration is given by r\'\'
r\'\'=<-cos(t),-sin(t),0>
At t=pi/2 it takes the value
r\'\'=<0,-1,0>

