Suppose that two tissues A and B are assayed for the activit

Suppose that two tissues A and B are assayed for the activity of enzyme X. If the results indicate that the activity of enzyme X is five times greater in tissue A than in tissue B under a variety of conditions what is the simplest explanation for these results.

Solution

This means that the pH optimum activity is different in tissue A and is 5 times better than the pH found in issue B.In other words the pH(A)= 5*pH(B),This is why the activity of enzyme is better in a higher pH level. pH matters.