If X Binomn12 p082 compute mean and variance of X round to t

If X Binom(n=12, p=0.82), compute mean and variance of X.

(round to two decimal places).

(a) Find the mean:

(b) Find the variance

Solution

a)
Mean ( np ) =9.84
b)
Standard Deviation ( npq )= 12*0.82*0.18 = 1.3309
Variance = npq = 12*0.82*0.18 = 1.7712