Find the solution of the differential equation that satisfie
Find the solution of the differential equation that satisfies the given initial condition.
x ln x = y(1 + sqrt(8 + y^2))y\', y(1) = 1
x ln x = y(1 + sqrt(8 + y^2))y\', y(1) = 1
Solution
x ln x = y(1 + sqrt(8 + y^2))y\'
x ln x = y(1 + sqrt(8 + y^2))(dy/dx)
x ln x dx = y(1 + sqrt(8 + y^2)) dy
int x ln x dx = int y(1 + sqrt(8 + y^2)) dy
1/4 x2 (2ln(x) - 1) + C = 1/2 y2 + 1/3 (8+y2)3/2
x=1 , y=1 -> -1/4 + C = 1/2 + 9
C = 9.75
Therefore the solution is:
1/4 x2 (2ln(x) - 1) + 9.75 = 1/2 y2 + 1/3 (8+y2)3/2
