Find the solution of the differential equation that satisfie

Find the solution of the differential equation that satisfies the given initial condition.
x ln x = y(1 + sqrt(8 + y^2))y\', y(1) = 1

Solution

x ln x = y(1 + sqrt(8 + y^2))y\'

x ln x = y(1 + sqrt(8 + y^2))(dy/dx)

x ln x dx = y(1 + sqrt(8 + y^2)) dy

int x ln x dx = int y(1 + sqrt(8 + y^2)) dy

1/4 x2 (2ln(x) - 1) + C = 1/2 y2 + 1/3 (8+y2)3/2

x=1 , y=1 -> -1/4 + C = 1/2 + 9

C = 9.75

Therefore the solution is:

1/4 x2 (2ln(x) - 1) + 9.75 = 1/2 y2 + 1/3 (8+y2)3/2

Find the solution of the differential equation that satisfies the given initial condition. x ln x = y(1 + sqrt(8 + y^2))y\', y(1) = 1Solutionx ln x = y(1 + sqrt

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