what is the answer to part 2 what is the magnitude of the fo

what is the answer to part 2? what is the magnitude of the force on the electron from the uranium ion?

and iron atom reside a dstance R-40.50 nm apart. The uranium atom is singly ionized the cried Calculate th distance r from the uranium atom necessary an electron to iron reside in equilibrium. ignore the insign ficant gravitational attraction between the paricles uranium ion ron ion r16.78 electron nm What is the magnitude of the force on the electron from the uranium ion?

Solution

The uranium is singly ionized implying that the net charge on the uranium is equal to that of one electron.

a.) For the electron, placed in between, to suffer no force, the net electric field at that point must be zero.

That is, Kq/r^2 - K2q/(40.50-r)^2 = 0

Hence, (40.5 - r) / r = 1.414; that is, r = 16.78 nm

b.) Now, the uranium has a net charge of 1.602 × 10^-19 coulombs.

Therefore, the net force on an electron at a distance of 16.78 nm = Kq^2 / d^2

That is F = 8.99 x 10^9 x 2.567 x 10^-38 / 16.78*16.78*10^-18 = 0.0819 x 10^-11 N