In the gear system shown gear 1 is located on the motor shaf

In the gear system shown, gear 1 is located on the motor shaft and turns 1200 rpm. Find the speed at which the load is being raised. D¹ is 21\" D² is 25\" N¹ is 32 N² is 84 N³ is 96

4. In the gear system shown, gear 1 is located Find the speed at which the load is being rais N84 21 dia. 25\" dia

Solution

given that

gear 1 =

speed =1200 rpm

D1 = 21 \" = 21x 25.4 = 533.4 mm no of teeth N1 = 84

D2 = 25\" = 25 x 25.4 = 635 mm no of teeth N2 = 96

D3 = ????? unmnown no of teeth N3 =32

question asked to fine the SPEED at which the load is being raised consider the load is 100kg x 9.8 =980 N

we have formula such that

TEETH ON DRIVEN WHEEL / TEETH ON DRIVING WHEEL = SPEED OF DRIVING WHEEL / SPEED OF DRIVEN WHEEL

i.e N3 / N1 = n1 / n3

=> 32/ 84 = 1200/n3

=> n3 = 1200x84 / 32

=> n3 = 3150rpm

TEETH ON DRIVEN WHEEL / TEETH ON DRIVING WHEEL = SPEED OF DRIVING WHEEL / SPEED OF DRIVEN WHEEL

i.e N2 / N3 = n3 / n2 ( we know n3 = 3150rpm )

=> 96/ 32 = 3150 / n2

=> n2 = 1050 rpm

so speed n1 = 2100 rpm , n2 = 1050 rpm , n3 = 3150 rpm are the speeds at which load is being raised ,,