Homework SourseFind an equation of the tangent line to the graph of the equ
Find an equation of the tangent line to the graph of the equation at the given point.
arctan(xy) = arcsin(5x + 5y), at (0, 0)
y=
arctan(xy) = arcsin(5x + 5y), at (0, 0)
y=
Solution
[1/(1+x^2y^2)] (y + xy\') = [1/(1 - (5x+5y)^2)^1/2] (5 + 5y\')
at (0,0)
0 = 5 + 5y\'
y\' = -1
so, equation of the tangent is-
y/x = -1
y = -x
x + y = 0
![Find an equation of the tangent line to the graph of the equation at the given point. arctan(xy) = arcsin(5x + 5y), at (0, 0) y=Solution[1/(1+x^2y^2)] (y + xy\'](/WebImages/30/find-an-equation-of-the-tangent-line-to-the-graph-of-the-equ-1083863-1761569599-0.webp "Find an equation of the tangent line to the graph of the equation at the given point. arctan(xy) = arcsin(5x + 5y), at (0, 0) y=Solution[1/(1+x^2y^2)] (y + xy\'")
