Find V2 considering V1 5 expjpi6 Solutionv15ej30 v15cos30js
Find V2, considering V1 = 5 exp(jpi/6)
Solution
v1=5*e^(j30)
v1=5[cos30+jsin 30]=(4.33+j2.5) =5<30 volts
from the circuit v1=5<30 volts
apply nodal analysis at node v2
(v2-5<30)/(-j2)+v2/(j1)+v1/2=0
solve the above equation
v2=7.07<-104.9 volts.
![Find V2, considering V1 = 5 exp(jpi/6) Solutionv1=5*e^(j30) v1=5[cos30+jsin 30]=(4.33+j2.5) =5<30 volts from the circuit v1=5<30 volts apply nodal analys Find V2, considering V1 = 5 exp(jpi/6) Solutionv1=5*e^(j30) v1=5[cos30+jsin 30]=(4.33+j2.5) =5<30 volts from the circuit v1=5<30 volts apply nodal analys](/WebImages/30/find-v2-considering-v1-5-expjpi6-solutionv15ej30-v15cos30js-1084080-1761569740-0.webp)