Find V2 considering V1 5 expjpi6 Solutionv15ej30 v15cos30js

Find V2, considering V1 = 5 exp(jpi/6)

Solution

v1=5*e^(j30)

v1=5[cos30+jsin 30]=(4.33+j2.5) =5<30 volts

from the circuit v1=5<30 volts

apply nodal analysis at node v2

(v2-5<30)/(-j2)+v2/(j1)+v1/2=0

solve the above equation

v2=7.07<-104.9 volts.

 Find V2, considering V1 = 5 exp(jpi/6) Solutionv1=5*e^(j30) v1=5[cos30+jsin 30]=(4.33+j2.5) =5<30 volts from the circuit v1=5<30 volts apply nodal analys

Get Help Now

Submit a Take Down Notice

Tutor
Tutor: Dr Jack
Most rated tutor on our site