FBD Frame 2MA0 7 mEy 45 m700N 0 E 450 N 3 F 0 A700 N450 N0

FBD Frame: 2MA-0: 7 m)Ey (4.5 m)700N) 0 E., = 450 N- 3 F, -0: A,-700 N+450 N-0 A, 250 Nt Dimensions inm FBD Member ABC: EMc : 0: (1 mx700 N ) _ (Inn)(250 N)-(3m) Ax:0 A, = 150.0 N . OON so E,-150.0 N

Solution

when we consider total frame only external forces(reaction forces) at supports are considered

but when we consider the individual frame then the internal components at all pins wiil be consider

 FBD Frame: 2MA-0: 7 m)Ey (4.5 m)700N) 0 E., = 450 N- 3 F, -0: A,-700 N+450 N-0 A, 250 Nt Dimensions inm FBD Member ABC: EMc : 0: (1 mx700 N ) _ (Inn)(250 N)-(3

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