FBD Frame 2MA0 7 mEy 45 m700N 0 E 450 N 3 F 0 A700 N450 N0
     FBD Frame: 2MA-0: 7 m)Ey (4.5 m)700N) 0 E., = 450 N- 3 F, -0: A,-700 N+450 N-0 A, 250 Nt Dimensions inm FBD Member ABC: EMc : 0: (1 mx700 N ) _ (Inn)(250 N)-(3m) Ax:0 A, = 150.0 N . OON so E,-150.0 N  
  
  Solution
when we consider total frame only external forces(reaction forces) at supports are considered
but when we consider the individual frame then the internal components at all pins wiil be consider

