A punch recipe calls for 15 L of fruit juice and 700mL of gi

A punch recipe calls for 1.5 L of fruit juice and 700mL of gingerale. How much fruit juice is needed for 2.5 L of gingerale?

Note:1 L = 1000mL

Solution

This is a proportions problem, Fruit Juice / Gingerale. First, get all your units the same, so 700ml = .7 L. Now set up the proportion:

1.5 L Fruit Juice / .7 L Gingerale = x L Fruit Juice / 2.5 L Gingerale, so

1.5 / .7 = x / 2.5

.7x = 1.5 * 2.5

.7x = 3.75

x = 5.36 L