Please include a punnet square so that I can understand the

Solution

Answer:

Wild wings = c+ ; curved wings= c

Wild eyes = se+ ; sepia eyes=se

c+c+ se+se+ X cc sese----------------Parents

c+ se+ c se---------------Gametes

c+c se+se (wild wings & wild eyes)----F1 (males and females are equal)

c+c se+se X    c+c se+se

F2

Phenotypes= (both wild) : (wild wings & sepia eyes) : (curved wings & wild eyes) : (curved wings & wild eyes)

Phenotypic ratio: 9 : 3 : 3 : 1

Genotypes:

c+c+ se+se+ : c+c+ se+se : c+c+ sese : c+c se+se+ : c+c se+se : c+c sese : cc se+se+ : cc se+se : cc sese

Genotypic ratio: 1 : 2 : 1 : 2 : 4 : 2 : 1: 2 : 1

In F2 ration also, all females and males are equal percentage as the genes are present on the autosomes.