in exercise 97102 find the indicated trigonometric value in
in exercise 97-102, find the indicated trigonometric value in the specified quadrant sec theta + -9/4 quadrant III tan theta
Solution
sec theta = -9/4
hypotenuse =9 , adjacent side =4
opposite side2+adjacent side2 =hypotenuse2
opposite side2+42 =92
opposite side2+16 =81
opposite side2=65
opposite side=65
tan is positive in ||| quadrant
tan theta =oppositeside/adjacent side
tan theta =(65)/4
