75lnxln2 solve for xSolution07 5lnxln2 Taking natura logar

.7=5^(lnx/ln2) solve for x

0.7 = 5^(lnx/ln2) . Taking natura logarithms of both the sides, we have ln(0.7) = ( lnx/ln2)ln5.
Therefore, lnx = [ln (0.7)* ln2] / ln5 =( - 0.356674943)*(0.69314718) / ( 1.609437912) = ( - 0.24722823)/ ( 1.609437912 = - 0.153611536 . Therefore, x = e^{( - 0.153611536)} = 0.657605105