What am I missing here Find a thirddegree polynomial Px that

What am I missing here?

Find a third-degree polynomial P(x) that has zeros at x = -3, x = 3, and x = 4, and whose x-term has coefficient 45. P(x) = x^3 - 4x^2 - 9x - 36

When a zero is at a, the factor that resulted in that zero is x-a.

Find the factor for each zero.

x=-3, the factor is x+3

x=3, the factor is x-3

x=4, the factor is x-4

The polynomial includes the factors (x+3)(x-3)(x-4) = (x^2 - 9)(x - 4) = x^3 - 4x^2 - 9x + 36

The x term has a coefficient of -9

-5 * -9 = 20, so multiply the polynomial by -5.

-5(x^3 - 4x^2 - 9x + 36) = -5x^3 + 20x^2 + 45x - 180 = 0