Particle moving along the x axis is located at 172m at 179s

Particle moving along the x axis is located at 17.2m at 1.79s and at 4.48m at 4.28s. find its displacement during this time interval. answer in m.

What is its average velocity during this time interval? answer in units of m/s. Calculate the particle\'s average speed during this time interval and answer in units of m/s.

Solution

The displacement of the particle from 17.2 m to 4.48 meter =4.48m-17.2m = -12.72 m during the time interval of (4.28s-1.79s )=2.49 secs.

Average velocity = displacement /time duration = -12.72/2.49=-5.1084m/s

The negative sign indicates that the direction of displacement and velocity are towards the origin .

The average speed during the interval = magnitude of displacement / time duration= 12.72/2.49=5.1084m/s