Three identical capacitors are connected in series with a to

Three identical capacitors are connected in series with a total capacitance of 5.92pF. What is the capacitance of each capacitor?

Solution

3 identical capacitors (c) are in series

=>total capacitance(Ct) 1/Ct= 1/c+1/c+1/c

                                1/5.92pF= 3/c

                                 c= 3*5.92pF = 17.79pF (option D)