Given a triangle with side a 91m A9101degree side b 735m a

Given a triangle with side a = 91m, (A)91.01degree side b = 73.5m, and angle A = 39degree, (B) 30.55degree (C) 50.83degree find angle B. (D) 110.45degree

Solution

a = 91 ; b= 73.5 ; A = 39 deg

Use sine rule to solve for angle

a/sinA = b/sinB

91/sin39 = 73.5/sinB

sinB = 73.5*sin39/91 = 0.508

B = 30.55 deg

Option B