Homework Soursemath Differentiate y 2sin3x1cos3x1SolutionWe have to differ
math
Differentiate y = 2sin(3x+1)cos(3x+1)
Solution
We have to differentiate y = 2sin(3x+1)cos(3x+1)
y = 2sin(3x+1)cos(3x+1)
=> y = sin [2(3x + 1)]
=> y = sin (6x + 2)
Use the chain rule.
y\' = cos (6x + 2) * 6
The required derivative is 6*cos (6x + 2)
![math Differentiate y = 2sin(3x+1)cos(3x+1)SolutionWe have to differentiate y = 2sin(3x+1)cos(3x+1) y = 2sin(3x+1)cos(3x+1) => y = sin [2(3x + 1)] => y = s](/WebImages/30/math-differentiate-y-2sin3x1cos3x1solutionwe-have-to-differ-1084557-1761570053-0.webp "math Differentiate y = 2sin(3x+1)cos(3x+1)SolutionWe have to differentiate y = 2sin(3x+1)cos(3x+1) y = 2sin(3x+1)cos(3x+1) => y = sin [2(3x + 1)] => y = s")
