Oxygen O2 occupies volume of 0135 m3 at 222 K Determine the

Oxygen (O_2) occupies & volume of 0.135 m^3 at 222 K, Determine the mass of oxygen, in kg.

Solution

specific volume of oxygen - v

Pv = RT ----------ideal gas equation

v = RT/P

R = 0.2598 kJ/kg.K , P= P_atm = 101.325 kPa

v = 0.2598*222 / (101.325)

v = 5.69*10^-1 m³ / kg

mass = Volume/ v

mass = 0.135/5.69*10^-1

mass = 0.2372 kg