A centrifuge rotates at a rate that gives the bottom of the

A centrifuge rotates at a rate that gives the bottom of the test tube a linear speed of 89.3 m/s.

If the bottom of the test tube is 8.50 centimeters from the axis of rotation, what is the centripetal acceleration experienced there?

Solution

value of centripetal acceleration= v² /r here v is linear velocity and r is the radius

centripetal acceleration= (89.3*89.3)/8.50*10^-2 =938.18*10² =9.38*10⁴ m/sec²