A MARKETING STUDY OF 800 ADULTS IN THE 1834 AGE GROUP REPORT
A MARKETING STUDY OF 800 ADULTS IN THE 18-34 AGE GROUP REPORTED THE FOLLOWING INFORMATION:
-spent less than $100 on children\'s clothing per year: 75 responses
-spent $100 - $499.99 on children\'s clothing per year: 200 responses
-spent $500 - $999.99 on children\'s clothing per year: 25 responses
-spent nothing: the remainder
Develop a spreadsheet to estimate the sample mean and sample standard deviation of spending on children\'s clothing for this age group using measuring skewness and computing statistical measures from frequency distributions.
Solution
AMOUNT
Mid X
FREQUENCY F
F*X
F*X*X
0
0
500
0
0
0 -100
50
75
3750
187500
100-499.99
300
200
60000
18000000
500-999.99
750
25
18750
14062500
Total
800
82500
32250000
Mean =82500/800=103.125
Variance = =29714.88
SD=sqrt(var) =172.38
The data are skewed. Median is the best central tendency , in this case median
= average of 400,401 th observation =0
mode =0
range =(0, 999.99)
| AMOUNT | Mid X | FREQUENCY F | F*X | F*X*X |
| 0 | 0 | 500 | 0 | 0 |
| 0 -100 | 50 | 75 | 3750 | 187500 |
| 100-499.99 | 300 | 200 | 60000 | 18000000 |
| 500-999.99 | 750 | 25 | 18750 | 14062500 |
| Total | 800 | 82500 | 32250000 |

