What is the answer to this question A sample of 200 ROM comp

?What is the answer to this question?

A sample of 200 ROM computer chips was selected on each of 30 consecutive days, and the number of nonconforming chips on each day was as follows: 7, 18, 25, 14, 38, 22, 9, 28, 11, 27, 31, 17, 15, 23, 15, 17, 18, 20, 15, 17, 14, 18, 14, 22, 33, 17, 9, 19, 13, 29. Construct a p chart and examine it for any out-of-control points. (Round your answers to four decimal places.) Comment on the chart. All points are between these limits, so the process appears to be in control. The value of s on the 5th day lies above the UCL, so an out-of-control signal is generated. All points are between these limits, so the process appears to be out of control. The value of s on the 5th day lies below the LCL, so an out-of-control signal is generated. Most points are between these limits, so the process appears to be in control with respect to variability.

Solution

575

CI = p ± Z a/2 Sqrt(p*(1-p)/n)))
x = Mean
n = Sample Size
a = 1 - (Confidence Level/100)
Za/2 = Z-table value
CI = Confidence Interval
Mean(x)=575
Sample Size(n)=6000
Sample proportion (p) = x/n =0.096
Confidence Interval = [ 0.096 ±Z a/2 ( Sqrt ( 0.096*0.904) /6000)]
= [ 0.096 - 1.96* Sqrt(0) , 0.096 + 1.96* Sqrt(0) ]
= [ 0.089,0.103]

Option A graph is suitable

On the 5th day p = 38/200 = 0.19

The value of s on the 5th day lies above the UCL, so an out-of-control signal is generated.

	n	defects
	200	7
	200	18
	200	25
	200	14
	200	38
	200	22
	200	9
	200	28
	200	11
	200	27
	200	31
	200	17
	200	15
	200	23
	200	15
	200	17
	200	18
	200	20
	200	15
	200	17
	200	14
	200	18
	200	14
	200	22
	200	33
	200	17
	200	9
	200	19
	200	13
	200	29
Total	6000	575