Tan psi rdrd theta 02theta02 theta2 theta psi tan1pi2 5

Tan psi = r/(dr/d theta) = 0.2/theta/-0.2 theta^-2 = -theta psi = tan^-1(-pi/2) = -57.5184 degree psi = tan^-1(-pi/2) = -57.5184 degree + uparrow sigma F_r = ma_r: N_p cos (332. 4816 degree) = 0.5 (-0.7651) leftarrow sigma F theta = ma_theta; F = N_P sin (32.4816 degree) = 0.5 (-3.7982)

Solution

it is very simple along the y axis sine angle should do angle with horizontal but above it was calculated as with respective horizontal....ie 90-57.5184=32.4186 degrees