Consider the following quadratic equation x2 64 Step f of 2

Consider the following quadratic equation x^2 = 64 Step f of 2: Using the standard from ax^2 + bx + c = U of the given quatric equation, factor the left hand side of the equation into two linear factors

Solution

x²=64 => x²-64=0 => x²-(8)²=0 => (x-8)(x+8)=0 [Using identity (a-b)(a+b)=a²-b²]

=> x-8=0 or x+8=0 => x=8 or x=-8