Multilayer Absorber Mirror A DaDb bilayer period lambda r

Multilayer Absorber Mirror A = D_a+D_b = bi-layer period lambda = radiation wavelength The period A ~ 1/2 wavelength [for normal incidence) Layer thicknesses = 1/4 wavelength mlambda. = 2d sinetheta m=1, 2 If refractive indices of silicon and Molybdenum are close to 1, and the thickness of each layer is 3.4 nm, what is wavelength of light source to be obtained? (use Bragg\'s equation)

Solution

From bragg’s equation

(n2/n1)=(sin(q1)/sin(q2))

Whereas sin(q1)=1

Sin(q2)=(n1/n2)=(1)

Wavelength=((3.4*10^-9)*1)/8=1.5nm