613 Solution1Tension in the string is given by TmV2r a T1mV2

6.13

1.Tension in the string is given by

T=mV²/r

a)

T₁=mV²/r

T₂=m*V²/(2r) =0.5(mV²/r)

T₃=(2m)*V²/r =2(mV²/r)

T₄=(2m)*V²/(2r)=mV²/r

So order is

T₃>T₁=T₄>T₂

6.13 Solution1.Tension in the string is given by T=mV2/r a) T1=mV2/r T2=m*V2/(2r) =0.5(mV2/r) T3=(2m)*V2/r =2(mV2/r) T4=(2m)*V2/(2r)=mV2/r So order is T3>T1

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