In a cyclic process heat transfers arc 147 kJ 252 kJ 356

In a cyclic process, heat transfers arc + 14.7 kJ, - 25.2 kJ, - 3.56 kJ and + 31.5 kJ. What is the net work for this cyclic process?

Solution

Cyclic process:
When a system returns to its original state after completing a series of changes, then it is known that a cycle is completed. This process is known as cyclic process. In a cyclic process the initial and the final state is same. As the internal energy U of the system depends only on the state of the system so in a cyclic process the net change of internal energy U will be equal to zero i.e. U = 0. Hence from the first law:

U = 0 = q + w
Hence, q = – w

Hence from given data,W=-(14.7-25.2-3.56+31.5)

W=-17.44KJ