Network Delay 20 points Consider the case of sending one pac

Network Delay, 20 points): Consider the case of sending one packet of length L from source to destination over a path consisting of N links each of rate R (thus, there are N-1 routers between source and destination).

a- What is the end-to-end delay?

b-What is the end-to-end delay for sending P such packets back-to-back over the N links?

c-Now, each link is m meters, and the propagation speed along the link is s meters/sec. What is the end-to-end delay of sending one packet?

d-Following c), what is the end-to-end delay of sending P such packets back-to-back?

Solution

Answer:

a- End to end delay = N( L/R ) , where N is number of links , R = rate , L is the length of packet.

b- Wec already derived end to end delay = N(L/R)

Now , one packet = end to end delay = N(L/R)

P packet = p * ( end to end delay ) = P [ N(L/R) ]

c - End to end delay = N ( m/s) , where N is the links , m is the distance and s /sec is the velocity.

d- one end to end dealy = N(m/s)

P end to end delay = P[N(m/s)]