tan x 16 cos x 0 find sin 2x cos 2x and tan 2xSolution tan
tan x = ?1/6, cos x > 0 (find sin 2x, cos 2x, and tan 2x)
Solution
tanx = -1/6 tan2x = (2tanx)/(1-tan²x) = (2(-1/6))/(1 - (-1/6)²) = (-1/3)/(1+(1/36)) = (-1/3)/(37/36) = -37/108 SOHCAHTOA sin = O/H = opposite/hypotenuse cos = A/H = adjacent/hypotenuse tan = O/A = opposite/adjacent tan2x = O/A = -37/108 A² + O² = H² 37² + 108² = H² H = 114.16