Find an equation for the hyperbola described Graph the equat

Find an equation for the hyperbola described. Graph the equation

Center at (4, -5); Focus at (10, -5); Vertex at (5, -5)

Write an equation for the hyperbola

Graph the equation

(x-h)²/a² - (y - k)²/b² =1

now as the center is at (4,-5) ,h = 4, k = -5

distance between vertex and centre = 1 so ,a =1

also distance between center and focus = 6 = ae = sqrt(a² + b²)

b² = 36 - 1 = 35

equation of hyperbola = (x-4)² - (y + 5)²/35 =1