Given that u Tu and v Tv as well as u Av show that A Tt

Given that u\' = Tu and v\' = Tv as well as u = Av. show that A = T^t A\' T Notice that T is the transformation matrix with TT^t = I, u and v are vectors, and A are second rank tensor. Using only equations given here, nothing else.

To show TA=A\'T (as T^tT = Id)

Apply both on v and show that they are equal.

TAv = Tu =u\'

A\'Tv= A\'v= u\'.

Hence the claim

$Given that u\' = Tu and v\' = Tv as well as u = Av. show that A = T^t A\' T Notice that T is the transformation matrix with TT^t = I, u and v are vectors, and$

Given that u Tu and v Tv as well as u Av show that A Tt

Solution

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