Write a tangent function hx such that the halfway points on
Write a tangent function, h(x), such that the halfway points on one period are (- pi/2, -2) and (pi/2, 4)
Solution
period = 4*(pi/2) = 2pi
b = pi/2pi = 1/2
y = a*tan(bx) +d
(-pi/2 , -2) and (pi/2 , 4)
plug these points:
-2 = a*tan(-pi/4) +d
-2 = -a +d ------(1)
4 = a*tan(pi/4) +d
4 = a +d ------(2)
we get d = 1 ; a = 3
So, y = 3tan(x/2) +1
