A bacterial community has 12 mgL of biomass at t 1 h and 34

A bacterial community has 1.2 mg/L of biomass at t = 1 h, and 3.4 mg/L of biomass at t = 6 h. what would be the predicted biomass concentration at 10 h (assuming exponential growth still applies)? What is the doubling time?

Solution

the predicted biomass concentration after 10 hrs would be approximately 8.22mg/L.

doubling time is 3.28 hrs

DoublingTime=durationlog(2 )/ log(FinalConcentration)log(InitalConcentration).

duration is 5hrs (6-1)

initial conc=1.2, final conc =3.4

so, DT=5*log2/log(3.4)-log(1.2)=3.288 which is the doubling time in hrs.

biomass is exponential increase, so 2^n, in 10hrs the no of cycles are 10/3.28=3.04, 2^3.04=8.22mg/L