Assume that car number plates are sequenced as follows DLV33

Assume that car number plates are sequenced as follows: DLV334 -->DLV335-->....DLV339-->DLV340-->....DLV999-->DLW000 and so on. Using this sequence, how many number plates are there between DLV334 and DNU211 inclusive?

Solution

Numbers in DLV000 to DLZ999= 5 x 10 x 10 x 10 =5000

Numbers in DLV334 to DLZ999=5 x 10 x10 x 10 -333 = 4667 (i)

Numbers in DMA000 to DMZ999= 26 x 10 x 10 x 10 = 26000 (ii)

Numbers in DNA000 to DNT999 = 20 x 10 x 10 x 10 = 20000 (iii)

Numbers in DNU000 to DNU211= 1x10x10+1x10x10+11=211 (iv)

Number plates are there between DLV334 and DNU211 inclusive

=(i)+(ii)+(iii)+(iv)

=4667+26000+20000+211

=50878