MKF is a farming manufacturer The product consist of two com
Solution
Given Values:
Press area: Number of Machines = 3 / Number of workers = 3
Cutting & Shaping area: Number of Machines = 2 / Number of workers = 2
Assembly area: Number of workers = 4
workers needed for Setting up of machine = 3
Step I: (Calculation of weekly production capacity)
We know that the cycle time for each shop area & worker is mentioned in the table.
So, 1) Cycle time for press = 3. Therefore hourly production = 60/3 = 20
Weekly production = 20*40 = 800 products/week
2) cycle time for cutting & shaping area = 7 min/pc
Hourly production = 60/7 = 8.57 = 8.00 approx
Weekly production = 40*8 = 320 products/week
3) Cycle time for one assemly worker = 20 min/pc
Hourly production = 60/20 = 3 products/week
Weekly production = 3*40 = 120 products/week
Step II
Consider, there are five working days of the factory and each shift is of 8 hours/day.
Factory capacity per week = (No. of shifts) * (No.of hours a day) * (No. of machines) * (No. of days a week)
= 1 * 8 * 5 * 5 = 200 standard hours a week
Step III:
Machine capacity is 200 standard hours per week with using 3 press machines & 2 cutting/shaping machines.
When the company increases the production capacity to 600 pc/week
then the required number of machines are given as: press shop = 6 & number of cutting & shaping machines = 6. The workers required in the assembly area = 12.
Workers required for the setting up of machines = 9 number.
Step III:
Utilisation rate of press machine:
Ur =(300-200) / (6-3) = 33.33 %
Utilisation rate of cutting & shaping machine:
Ur = (300 - 200) / (3-2) = 100 %
utilisation rate of assembly worker
Ur = (300 - 200) / (6-4) = 50 %
Utilisation rate of worker for setting up of machine
Ur = (300 - 200) / (4 - 3) = 100 %
Step IV:
The company is producing C component. After production of 390 pc/week with the use of above readings, the maximum weekly production rate of component C is
Pr = 3 * 4 * 5 * 8 * 1 = 480 pc/week.

